AWS i4g.2xlargevsAWS i4i.2xlarge

i4g.2xlarge pairs 8 vCPUs with 64GB of RAM at $0.6178/hr On-Demand (about $445/mo at 24×7). i4i.2xlarge pairs 8 vCPUs with 64GB at $0.6860/hr (~$494/mo). i4g.2xlarge is 11% cheaper per hour than i4i.2xlarge ($0.0682/hr gap).

Both are generation-4 storage-optimized (NVMe SSD) instances, but they run on different silicon: **i4g.2xlarge** is AWS Graviton (ARM64), **i4i.2xlarge** is Intel Xeon (x86_64). AMD variants (suffix `a`) are typically 10% cheaper than Intel siblings at comparable single-thread performance. Graviton variants (suffix `g`) are usually 20–40% cheaper but require ARM64-compatible binaries — most modern Linux stacks are fine, but verify any compiled extensions, native modules, or third-party binaries before migrating. Same vCPU/RAM ratio, same network performance class, different processor.

On raw price-per-performance, the two are i4g.2xlarge delivers ~5% more single-thread Sysbench score per dollar (4549 vs 4338 points per $1/hr). That's the cleanest signal we have for "which one runs your workload faster per dollar," but it only matters if your workload is single-thread-bound; for parallel workloads the multi-core scores (22133 vs 12372) are what to weigh. Spot pricing flips many of these comparisons — when i4g.2xlarge drops to $0.1699/hr and i4i.2xlarge drops to $0.2714/hr, the cheap-per-hour winner can swing meaningfully.

In practice, pick i4g.2xlarge when your workload is closer to storage-optimized (NVMe SSD) (I/O-bound work needing low-latency NVMe local storage — NoSQL, search). Pick i4i.2xlarge when it's closer to storage-optimized (NVMe SSD) (I/O-bound work needing low-latency NVMe local storage — NoSQL, search). When neither side is obviously right, the cheaper hourly rate usually wins for fault-tolerant batch workloads, while the higher single-core score usually wins for latency-sensitive web traffic. The regional pricing tables linked from each instance page below show where each is currently cheapest — sometimes a >20% regional gap flips the comparison entirely.